Question

asymptotes of this function:

Answer 1

\[\frac{ 2x-1 }{ x+2 }\]

Answer 2

Horizontal: x+2= 0, x=-2...how for the vertcial one?

Answer 3

The vertical asymptote would be x=-2 (because adding -2 to 2 would give you a zero in the denominator), and the horizontal asymptote would be 2 (as calculated by dividing 2x/x)

Answer 4

oh...sorry, I did the vertical before...and what would the horizontal be?

Answer 5

Vertical asymptote is when y goes to infinity.
Horizontal asymptote is when x goes to infinity.

To find the horizontal asymptote, find the limit of (2x - 1) / (x + 2) as goes to infinity.

Answer 6

y=2 :)

Answer 7

yes.

Answer 8

So the range is (-inf,2)U(2,INF)
?

Answer 9

Yes the range is correct.
Domain is (-inf, -2) U (-2, inf)