Elizabeth brought a box of donuts to share. There are two-dozen (24) donuts in the box, all identical in size, shape, and color. Four are jelly-filled, 10 are lemon-filled, and 10 are custard-filled. You randomly select one donut, eat it, and select another donut. Find the probability of selecting a lemon-filled donut followed by a custard-filled donut. Write your answer as a fraction in simplest form.

Question

anonymous · Answer

Oh this is a fun question.  So do you know what the given is?

anonymous · Answer

the probability has c hanged for the second time where you take a donut because there is one less donut with lemon filling.

directrix · Answer

10 Lemons
10 Custards
24 doughnuts

The probability of selecting a lemon doughnut first is 10/24 where 10 is the number of successes (lemon) and 24 is the number of possibilities.

On the second doughnut, the probability of choosing a custard is 10/23 where 10 is the number of successes (custard) and 23 is the number of possibilities. (That one fewer because one doughnut has already been eaten.)

The probability of selecting a lemon-filled doughnut followed by a custard-filled doughnut is 10/24 * 10/23. Multiply those and simplify.

Post what you get.  @oldspice21