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Mathematics 14 Online
OpenStudy (anonymous):

Hi all! I've been struggling with this problem :) "A tank has 5000L of pure water. Brine containing 30g of salt/liter is pumped into the tank at a rate of 25L/minute. 1. Show the concentration of salt after t minutes in grams/liter is C(t)=(30t)/(200+t) 2. What happens to the concentration as t->infinity?"

OpenStudy (anonymous):

2. the solution will go to 30g salt/Liter as t->infinity

OpenStudy (anonymous):

cool that was my answer for 2 :)

OpenStudy (anonymous):

after 1 minute there will be 30 g of salt in 5025 litters

ganeshie8 (ganeshie8):

^^ so, after \(t\) minutes there will be \(30*t\) g of salt in \(5000 + 25t\) liters

ganeshie8 (ganeshie8):

Oh wait a sec, but we're getting 25L of salty water into the tank, lets account that

ganeshie8 (ganeshie8):

it wud be :- after \(t\) minutes there will be \(25*30*t\) g of salt in \(5000+25t\) liters

OpenStudy (anonymous):

so its a matter of simplifying 750t / (5000 + 25t) ?

OpenStudy (anonymous):

yes C(t) = 25 *30t ----------- = 30t / (200 + t) 25( 200 + )

OpenStudy (anonymous):

* correction 25 ( 200 + t)

OpenStudy (anonymous):

thats the denominator in middle term

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