Radicals ._. @ganeshie8 Am I doing this right?

Question

lifeisadangerousgame · Answer

First I had the problem
then I put $$\sqrt{8 \times 6 \times y \times y}$$
Is that right so far?

ganeshie8 · Answer

nope, not ok 
cuz you're doing it reverse

ganeshie8 · Answer

$\large  \sqrt{48y^2}$

ganeshie8 · Answer

convert the radical to exponent

ganeshie8 · Answer

$\large  \sqrt{48y^2}$

$\large  (48y^2)^{\frac{1}{2}}$

ganeshie8 · Answer

$\large  \sqrt{48y^2}$

$\large  (48y^2)^{\frac{1}{2}}$

$\large  (48)^{\frac{1}{2}} (y^2)^{\frac{1}{2}}$

ganeshie8 · Answer

$\large  \sqrt{48y^2}$

$\large  (48y^2)^{\frac{1}{2}}$

$\large  (48)^{\frac{1}{2}} (y^2)^{\frac{1}{2}}$

$\large  (48)^{\frac{1}{2}}y$

ganeshie8 · Answer

fine so far ?

lifeisadangerousgame · Answer

Fine so far

ganeshie8 · Answer

next, use this :-
48 = 16x3

ganeshie8 · Answer

$\large  \sqrt{48y^2}$

$\large  (48y^2)^{\frac{1}{2}}$

$\large  (48)^{\frac{1}{2}} (y^2)^{\frac{1}{2}}$

$\large  (48)^{\frac{1}{2}}y$

$\large  (16 \times 3)^{\frac{1}{2}}y$

$\large  (16)^{\frac{1}{2}}  (3)^{\frac{1}{2}} y$

ganeshie8 · Answer

$\large  \sqrt{48y^2}$

$\large  (48y^2)^{\frac{1}{2}}$

$\large  (48)^{\frac{1}{2}} (y^2)^{\frac{1}{2}}$

$\large  (48)^{\frac{1}{2}}y$

$\large  (16 \times 3)^{\frac{1}{2}}y$

$\large  (16)^{\frac{1}{2}}  (3)^{\frac{1}{2}} y$

$\large  (4^2)^{\frac{1}{2}}  (3)^{\frac{1}{2}} y$

ganeshie8 · Answer

$\large  \sqrt{48y^2}$

$\large  (48y^2)^{\frac{1}{2}}$

$\large  (48)^{\frac{1}{2}} (y^2)^{\frac{1}{2}}$

$\large  (48)^{\frac{1}{2}}y$

$\large  (16 \times 3)^{\frac{1}{2}}y$

$\large  (16)^{\frac{1}{2}}  (3)^{\frac{1}{2}} y$

$\large  (4^2)^{\frac{1}{2}}  (3)^{\frac{1}{2}} y$

$\large  4  (3)^{\frac{1}{2}} y$

ganeshie8 · Answer

$\large  \sqrt{48y^2}$

$\large  (48y^2)^{\frac{1}{2}}$

$\large  (48)^{\frac{1}{2}} (y^2)^{\frac{1}{2}}$

$\large  (48)^{\frac{1}{2}}y$

$\large  (16 \times 3)^{\frac{1}{2}}y$

$\large  (16)^{\frac{1}{2}}  (3)^{\frac{1}{2}} y$

$\large  (4^2)^{\frac{1}{2}}  (3)^{\frac{1}{2}} y$

$\large  4  \sqrt{3} y$

$\large  4y  \sqrt{3}$

ganeshie8 · Answer

Done. see if ti makes soem sense :)

lifeisadangerousgame · Answer

like it makes sense how you got the answer, I can see how you got it and the steps, but I still don't understand how I would do it if I had to do this on my own

ganeshie8 · Answer

ikr.... practice few problems, until u feel confident.
there is no other way !

lifeisadangerousgame · Answer

Definitely, thanks Ganeshie!

ganeshie8 · Answer

np :)
remember this :-
when u pull 4^2 out from a radical, it becomes 4

ganeshie8 · Answer

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ganeshie8 · Answer

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