Question

Help Please! I Know All These Links May Seem Like Alot But Its Only The Questions, Formula, & Problem.
(ALGEBRA 2 Project).


http://www.image-maps.com/uploaded_files/6201310241637038_Screen%20shot%202013-10-24%20at%204.35.59%20PM.png

http://www.image-maps.com/uploaded_files/6201310241637038_Screen%20shot%202013-10-24%20at%204.35.51%20PM.png

http://www.image-maps.com/uploaded_files/6201310241637038_1_Screen%20shot%202013-10-24%20at%204.48.59%20PM.png

Answer 1

Guidance Needed,

Answer 2

I'll try to figure out the graphing myself because i know thats alot, i just need help in setting the problem up, please help =\ damsel in distress. lol

Answer 3

do you not have the angle which he hit the ball? or do you get to make it up?

Answer 4

i havnt had physics for awhile but i think you need that angle to get vx and vy

Answer 5

No im sorry, =( no angle.. I can take a quick pic of the whole paper but i didnt do that so i wouldnt confuse people but it says nothing on angle that i remember @alec.mccarty

Answer 6

it says the scenario you have chosen so it may want you to pick one but without it i do not see how the calculations are possible

Answer 7

h = -16t^2 + vt + s

This is the formula for the height reached by the golf ball (that is the y-axis in the graph) after time t. Here v is the vertical velocity. s is the initial height above the ground (like hitting a golf ball from a cliff).

To simplify, you can assume s = 0 and so the golf ball is hit from the ground.
Put s = 0 and v = 100 ft / sec in the formula.

h = -16t^2 + 100t is the equation representing the scenario we have chosen.

Graph h as a function of t. It will be a parabola that opens downwards.

Answer 8

1) The equation is: h = -16^t2 + 100t where h bis the height in feet of the golf ball measured from the ground and t is the time in seconds. We have assumed s = 0 which means the golf ball is assumed to be hit from the ground and not from a cliff or below ground.

2) Graph h = -16t^2 + 100t


3) To find the maximum height reached, find the derivative of h with respect to t and equate it to 0 and solve for t.

4) To find the maximum height, put the value you found for t in part 3)
into -16t^2 + 100t and calculate h

5) To find how long before the ball hits the ground, put h = 0 and solve for t.
That is, h = -16t^2 + 100t = 0
Factor out t
t(-16t + 100) = 0
t = 0 or -16t + 100 = 0
solve for t.