Identify the vertex and axis of symmetry.
y=-2
is x ^2 or ^3
Is it what?
nvm
Does anybody know the answer?
wait im trying xD
is there a 1 on your choices?
If you differentiate with respect to x, to get the function \[dy/dx = 2x-2\] And let it = 0 to find the vetex you will get \[2x-2=0\] so 2x=2 , x = 1 Now we know the x co-ordinate to find the y co-ordinate substitute the x value into the original equation to get \[y= (1)^2-2(1)-1\] y=-2 So the vertex is at (1,-2) The axis of symmetry is the vertical line which passes through -2 which is x = -2 Sorry it took so long but started solving it the wrong way and realised only after finishing.
woo i got half of it :)
Yep u did get half of it.. Thanks guy's. :)
Thanks heat, and sorry it took so long but started completing the square and it just went horribly wrong :s
Haha i understand, but don't worry its cool.
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