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OpenStudy (anonymous):
y=-2
OpenStudy (anonymous):
is x ^2 or ^3
OpenStudy (anonymous):
Is it what?
OpenStudy (anonymous):
nvm
OpenStudy (anonymous):
Does anybody know the answer?
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OpenStudy (anonymous):
wait im trying xD
OpenStudy (anonymous):
is there a 1 on your choices?
OpenStudy (anonymous):
If you differentiate with respect to x, to get the function \[dy/dx = 2x-2\]
And let it = 0 to find the vetex you will get \[2x-2=0\] so 2x=2 , x = 1
Now we know the x co-ordinate to find the y co-ordinate substitute the x value into the original equation to get \[y= (1)^2-2(1)-1\]
y=-2
So the vertex is at (1,-2)
The axis of symmetry is the vertical line which passes through -2 which is x = -2
Sorry it took so long but started solving it the wrong way and realised only after finishing.
OpenStudy (anonymous):
woo i got half of it :)
OpenStudy (anonymous):
Yep u did get half of it.. Thanks guy's. :)
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OpenStudy (anonymous):
Thanks heat, and sorry it took so long but started completing the square and it just went horribly wrong :s