write the equation of a line : perpendicular to y=3x-1, through(-3,1)
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OpenStudy (anonymous):
alright, we will first need to identify the slope of the line from the equation give, can you do that?
what is m, in the equation y=3x-1?
OpenStudy (anonymous):
3/1
OpenStudy (anonymous):
yep ^_^
OpenStudy (anonymous):
now we need to turn that slope into the slope of a perpendicular line.
so we do (-1)*m for the first step, then flip the fraction upside down. can you do that?
OpenStudy (anonymous):
-1/3
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OpenStudy (anonymous):
right again ^_^
OpenStudy (anonymous):
so now we have the slope of the perpendicular line, now we need to make a 'y=mx+b' equation for it,
so we now know m, we were given (x,y) in the question, so plug those into the y=mx+b equation and solve for 'b'
OpenStudy (anonymous):
b=0
OpenStudy (anonymous):
3 for 3, nice work ^_^
OpenStudy (anonymous):
so, now the last step is to write the equation of the perpendicular line in 'slope-intercept' form
so plug in m and b into this equation only, and you are done ^_^
y=mx+b
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OpenStudy (anonymous):
y=-1/3x+b
OpenStudy (anonymous):
don't forget b=0, so put that in
OpenStudy (anonymous):
y=-1/3x
OpenStudy (anonymous):
esta correcto ?
OpenStudy (anonymous):
yep, that is correct
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