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Algebra 24 Online
OpenStudy (anonymous):

this

OpenStudy (anonymous):

link

OpenStudy (solomonzelman):

real number could be anything, it doesn't have to be positive or a whole number, it is even irrational. I would say that C is the only one that does not fir, b/c it is square root of -1 and therefore an imaginary number...

OpenStudy (anonymous):

This is a bad question.

OpenStudy (anonymous):

why is tht

OpenStudy (solomonzelman):

Do you know what real number is?

OpenStudy (anonymous):

5

OpenStudy (anonymous):

It's defined at x = 4. It's defined as \(i\). I doubt if this is what they meant to ask.

OpenStudy (solomonzelman):

@Starr_Dynasty, if you know what a real number is, you can plug the choices into your equation you will see that C is equal to a square root of a negative number and C is the only not real number, otu of the choices you have!

OpenStudy (anonymous):

They meant to ask if it was real, not defined. Hence, bad question. Solomon's thinking is right if they had asked properly, though.

OpenStudy (solomonzelman):

@Starr_Dynasty, if that is from your book it should be crossed out and never aksed again. Haven't seen such a bad question!!!!!!!!

OpenStudy (anonymous):

Or, they could have specified \(f(x)\) had to be a real number, but they didn't, they just said \(x\) is real.

OpenStudy (anonymous):

Anyway, this question is incoherent so I'll just give you the answer they're probably expecting, which is B.

OpenStudy (anonymous):

tht was so so so so confusing

OpenStudy (anonymous):

It's a bad question.

OpenStudy (anonymous):

its a terrible one yet u managed to get it right

OpenStudy (anonymous):

What they are trying to teach you is that the square roots of negative numbers are not real numbers.

OpenStudy (anonymous):

I got it right by knowing what they were trying to teach you and assuming they asked that, instead of what they actually asked. :)

OpenStudy (anonymous):

wow lol

OpenStudy (anonymous):

Anyway, just file that one away and remember it. The square root of a number less than 0 is not a real number.

OpenStudy (anonymous):

thts cool

OpenStudy (anonymous):

(Because there is, after all, no real number you can multiply by itself to get a negative)

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