Question

Please help me with this

Answer 1

so if you are looking for the identical x-intercepts, then we know that y must equal zero.
so set the equation equal to zero, then solve for x,
dose that help...? ^_^ ya no?

Answer 2

still struggling , can you help me a little more with setting them equal to zero

Answer 3

ya ^_^ medal for your honesty!

Answer 4

'f(x)' is a fancy way of saying 'y'
so, when I say set y=0, i'm just saying set f(x) = 0
\[f(x) = 0 = \frac{ x+7 }{ x^{2} + 5x - 3 }\]
so we will want to factor the denominator, and chances are, there will be a "(x+7)" in it.
so
can you factor:
x^2 + 5x - 3
so it becomes something like this:
(x )(x )

Answer 5

okay, im trying, one second

Answer 6

actually, i lied to you :(
we need to use the quadratic equation on the denominator to find the values of x

Answer 7

okay lol

Answer 8

you remember the quadratic equation? or should I post it up?

Answer 9

i know it

Answer 10

^_^

Answer 11

ax^2 + bx + c =0

Answer 12

yup, thats part of it

Answer 13

wow, i'm really really really sorry,

Answer 14

I sometimes start teaching without solving it first, and I'm leading you down the wrong path!

Answer 15

I'm making it much harder than needs be.
lets start over ^_^
and we will be done in like 3 seconds doing it this new way

Answer 16

okay lol, thank you!