Question

How do you find the axis of symmetry and vertex with this function: f(x)=x^2-10x+32

Answer 1

For a quadratic function (a.k.a parabola), you can find the AOS using the formula:\[x=\frac{ -b }{ 2a }\] for equations of the form:
f(x) = ax^2 + bx + c

Note this AOS is just an x value. All you would then do is substitute that x-value into your f(x) and solve. That would give you the y-coordinate and you'd have an ordered pair that represents your vertex.

Answer 2

So is it (5,7) ?

Answer 3

You've got it!

Answer 4

Nice! Thank you