Question

PLEASE HELP

Which is the equation for the line perpendicular to y = – 5/3 x +11 1/3 and containing P(–2, 3)? (1 point)

Answer 1

A. Y-2 = -3/5(X-3)
B. -5/3x + 4 1/3
C. -3/5x + 4 1/5
D. 3/5 x +4 1/5

Answer 2

?

Answer 3

The m(slope) for second line is -1/-5/3 caz we want the line perpendicular .
So slope (m)is :
m=-1/-5/3=1/5/3=3/5
And we want that containing P(–2, 3) . so use this :
Y2-y=m(X2-x)
Y2=3
X2=-2
So we have :
3-y=3/5(-2-x)
-y=-6/5-3/5x
y=6/5+3/5x
Got it ?:)
@ReaganBeard

Answer 4

Yes i think

Answer 5

If have any problem say ...:)

Answer 6

So would it be B?

Answer 7

or would it be 3/5?

Answer 8

No i get it it's D

Answer 9

You say : Which one of 3 and -2 are x and y ?