Question

Write the equation of a line perpendicular to the line y = x - 3 and containing the point (8, -2).

Answer 1

Is there a formula for this or something?

Answer 2

Perpendicular lines have negative reciprocal slopes. So what is the slope of the equation you have, and what is the negative reciprocal of it?

Answer 3

(That's just the first step)

Answer 4

if this gradient/slope = 1 then the perpendicular gradient/slope= -1
therefor the equation = y=-x-3

Answer 5

not quite, @ayesha05. y = x - 3. The slope is 1, and the negative reciprocal is -1.

next, you need to take that slope and your point (8, -2) and put them in point slope form. do you know what that is, @ilmc1?

Answer 6

I got it- its y=x-3 y=-x+c -2=-8+c c=6 y=-x+6

Answer 7

yes thats what i was also wondering what happened to the -3

Answer 8

Thanks guys c:

Answer 9

you're welcome!