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Mathematics 19 Online
OpenStudy (anonymous):

whats the function of the attached graph?

OpenStudy (anonymous):

OpenStudy (anonymous):

Do you know what is hyperbola ??

OpenStudy (anonymous):

no but I can look. I think my x axis is (x-(-4) ?

OpenStudy (anonymous):

i see what a hyperbola is

OpenStudy (anonymous):

Its a shifted hyperbolic curve

OpenStudy (anonymous):

- (1/x+4) + -4?

OpenStudy (anonymous):

(1/x+2) -4?

OpenStudy (anonymous):

Its a shifted rectangular hyperbola . You can assume the equation of ractangular hyperbola & put the the values in the equations to find out constant terms

OpenStudy (anonymous):

this stuff is complicated but thank you

OpenStudy (anonymous):

I also need to get through basics of that . Cant tell u the wrong approach . I"ll get back on this :)

OpenStudy (ybarrap):

@mocham You can use the rectangular form of the hyperbolic function with horizontal/vertical asymptotes: http://en.wikipedia.org/wiki/Hyperbola#Rectangular_hyperbola_with_horizontal.2Fvertical_asymptotes_.28Cartesian_coordinates.29 It looks like h=-2 and k=-4: http://www.wolframalpha.com/input/?i=%28x%2B2%29%28y%2B4%29%3D1%2C-8%3Cx%3C8%2C-12%3Cy%3C4

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