Question

Trigonometric substitutions,

can you please help me with these?

https://www.dropbox.com/s/agmk6x5vvm0wne0/Screenshot%202013-10-25%2022.53.06.jpg

Answer 1

have a look...

Answer 2

why do I feel that this is totally irrelevant :o

Answer 3

I know there is a method to solve these, but unfortunately I don't remember it, there is a specific method.

Answer 4

top of the third page...

Answer 5

Ok I found it, wait , could you tell me the first three steps of lets say, 1 (a) ? I have like, completely forgotten it, all I need is to recall it.

Answer 6

like in the top of the third page, could we separate it in smaller steps ?

Answer 7

1a. Let x = a sin theta

Answer 8

ok

Answer 9

\[\sqrt{a^2-x^2}\Rightarrow \sqrt{a^2-a^2\sin^2\theta}= acos\theta\]

since x = a sin theta, dx = a cos theta

Answer 10

so I am in the step of int[sqrt(2^2 - sin^2(theta)aces(theta)

Answer 11

cos*

Answer 12

Now what ? @pgpilot326

Answer 13

why do I feel that this is totally irrelevant :o

Answer 14

I am a beginner.

Answer 15

didn't mean to hurt you ;p