Write an equation for a circle with center at (2,3) and radius of 6

Question

sepeario · Answer

(x - 0)² + (y - 0)² = 6² 
x² + y² = 36

anonymous · Answer

alrighty so it is x^2+y^2=36 :) thanks

aakashsudhakar · Answer

(h, k) --> (2, 3)
r = 6

The equation for a circle is...
(x - h)^2 + (y - k)^2 = r^2

Plug in your values to get your circle equation.

(x - h)^2 + (y - k)^2 = r^2
(x - 2)^2 + (y - 3)^2 = 36

^^ That's a satisfactory answer, or you can even get fancy if you like.

(x - 2)^2 + (y - 3)^2 = 36
(x^2 - 4x + 4) + (y^2 - 6x + 9) = 36
x^2 - 4x + y^2 - 6x + 13 = 36
x^2 - 4x + y^2 - 6x = 23

^^ That's also acceptable.

aakashsudhakar · Answer

x^2 + y^2 = 36 is not the correct equation for the circle.

anonymous · Answer

(x-2)^2+(y-3)^2=36

aakashsudhakar · Answer

Yes, that's correct.

anonymous · Answer

alright thanks