which of the following is equivalent to 2csc(2x)?
a. csc(x)
b. sec(x)
c. csc(x) sec(x)
d. sin(x) cos(x)
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OpenStudy (anonymous):
looky looky identity
there are only two things you need to recall here, really, apart from the more obvious ones... things like
\[\large \csc\theta = \frac1{\sin\theta}\]\[\large \sec\theta = \frac1{\cos\theta}\]
just remember that
\[\large \sin(2\theta) = 2\sin(\theta)\cos(\theta)\]
OpenStudy (anonymous):
hmm
OpenStudy (anonymous):
I'm feeling d., but is there a way to break it down?
OpenStudy (anonymous):
while I'd normally say trust your feelings, this is not the time for that :D
I don't actually know ^.^
OpenStudy (anonymous):
hmm
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OpenStudy (anonymous):
well, sin 2x=2 sin x cos x
OpenStudy (anonymous):
so would csc 2x= 1/2 sin x cos x?
OpenStudy (anonymous):
well naturally ;)
OpenStudy (anonymous):
so the 2csc would equal...
OpenStudy (anonymous):
hmm
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OpenStudy (anonymous):
multiply the whole expression by 2?
OpenStudy (anonymous):
yup
OpenStudy (anonymous):
so...
OpenStudy (anonymous):
that would still be 1/2 sin x cos x
OpenStudy (anonymous):
nopity nope :>
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OpenStudy (anonymous):
well
OpenStudy (anonymous):
2/4 sin x cos x=1/2 sin x cos x
OpenStudy (anonymous):
don't be silly :P
when you multiply a fraction by a number, you only multiply it with the numerator XD
OpenStudy (anonymous):
ahh
OpenStudy (anonymous):
so 2/2 sin x cos x?
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OpenStudy (anonymous):
sin x cos x?
OpenStudy (anonymous):
wait
OpenStudy (anonymous):
or 1/sin x cos x
OpenStudy (anonymous):
what does your heart tell you?
OpenStudy (anonymous):
1/ sin x cos x
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