I KEEP GETTING y=(1/6)x+43/6 but it doesn't look right... is that the answer???
that's what I got, yes
hmnm wait... shoot misread my own writing lol
one sec
hmmm nope.... it's correct
really?
\(\bf slope =m = \cfrac{1}{6}\qquad\qquad (5, 8)\\ \quad \\ y-y_1=m(x-x_1)\implies y-8=\cfrac{1}{6}(x-5)\implies y-8=\cfrac{1}{6}x-\cfrac{5}{6}\\ \quad \\ y = \cfrac{1}{6}x-\cfrac{5}{6}+8\implies y = \cfrac{1}{6}x-\cfrac{5}{6}+\cfrac{48}{6}\implies y = \cfrac{1}{6}x+\cfrac{53}{6}\)
woops, shoot, have a typo hold on
\(\bf slope =m = \cfrac{1}{6}\qquad\qquad (5, 8)\\ \quad \\ y-y_1=m(x-x_1)\implies y-8=\cfrac{1}{6}(x-5)\implies y-8=\cfrac{1}{6}x-\cfrac{5}{6}\\ \quad \\ y = \cfrac{1}{6}x-\cfrac{5}{6}+8\implies y = \cfrac{1}{6}x-\cfrac{5}{6}+\cfrac{48}{6}\implies \color{blue}{y = \cfrac{1}{6}x+\cfrac{43}{6}}\)
thanks :3
yw
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