Question

let g(x)= x+3/2x-5 find g(-3)

Can the denominator be a negative?

Answer 1

yes

Answer 2

it just can't be zero

Answer 3

would my answer be -(1/11) ?

Answer 4

no

Answer 5

\[g(x)=\frac{x+3}{2x-5}\]
\[g(-3)=\frac{-3+3}{2\times (-3)-5}=\frac{0}{-11}=0\]

Answer 6

but that doesn't mean its undefined?

Answer 7

no

Answer 8

\[\frac{a}{0}\] is undefined but \(\frac{0}{a}\) is \(0\)

Answer 9

oh okay

Answer 10

thanks