Question

h(x)=sqrt4-x find h(0) + h(-5)


what is h???

Answer 1

h is the function, h(x). Means h is a function of x.

Think of h(x) as being like y, like this
\[\large y = h(x) = \sqrt {4-x}\]
h( ) <==== whatever is inside the brackets, plug that in in place of x in sqrt(4-x).

h(0) means... what is h equal to, when x is 0? or think of it as what is y equal to, when x is 0.

Answer 2

y is equal to 5?

Answer 3

oh its -1 so its undefined

Answer 4

?

Answer 5

wait, what? no, y is defined for both of these x values

h(0) + h(-5)
^this means plug in x=0 ^ this means plug in x=-5

h(0) = sqrt (4-0)

h(-5) = sqrt (4- (-5))

Answer 6

would my answer be undefined ?

Answer 7

No... simplify everything inside the sqrt before taking the square root.

Answer 8

sqrt (4-0) = ???

sqrt (4- (-5)) = ???

then add the results together

Answer 9

my answer is 5 - i completely forgot to do the sqrt of 4 i hate when I miss simple things like that!

Answer 10

Good job :)

Answer 11

=) thank you