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Find f(x) if f(0)=1 and the tangent line at (x, f(x)) has slope 7x. Its been a long while since I have done one of these somebody please help!!
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is the slope \(7\) ? \(7x\) is not a slope
maybe... the problem says 7x... let me see if I can send you a screenshot
f'(x) = 7x Integrate both sides to find f(x). Put x = 0, y = 1 and find the constant.
oh that is an entirely different question the anti derivative is \(\frac{7x^2}{2}+C\)
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then you can solve for \(C\) since \[f(0)=1=C\]
so it will be \[\frac{ 7x^{2} }{ 2 }+1\]???
yes
do I need to further simplify it?
or leave it as is?
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