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OCW Scholar - Physics I: Classical Mechanics
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two bodies of mass ma and mb are dropped from two different hieghts a and b.the ratio times taken by the two bodies to drop through these distances is
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for a body of mass m dropped from a height h the time taken is independent of its mass it is given by \[t \alpha c \sqrt{h/g}\] since g is gravitational constant and c is a constnt of proportionnality hence\[t \alpha \sqrt{h}\] hence your answer will be \[t _{1}/t _{2}=\sqrt{a/b}\]
the ratio is 1/r squared....r is the distance
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