help me out... It is given that -1 is one of the roots of quadratic equation mx^2 - 3x - k = 0 where m and k are constants. Express m in term of k.
just plug in x=-1 in that equation as -1 is the root, it satisfies that equation
is it the answer ... m+3-k=0
yes, so m=k-3
ok, how about this question..... |dw:1382854286778:dw| express y in terms of x. how do i do this?
tricky.... let xy = Y 1/x=X you have 2 points, in XY plane, find the equation of line in terms of X and Y, can you ?
no
you don't know how to find equation of line when 2 points are given ? start by finding the slope, have the formula of slope with you ?
is the slope of the line is the gradient ? so can i make it using y-y=m(x-x)
yes, correct, use that and tell me the equation of line...
y-3= 5(x-2) y-3=5x-10 y=5x-7
correct! its actually Y=5X-7 now plug in back, X = 1/x , Y =xy
xy= 5/x - 7
yes, just isolate the 'y' by dividing both sides by 'x'
5/x^2 - 7/x
yes, i think thats correct.
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