OpenStudy (anonymous):

4u - (3u)

4 years ago
OpenStudy (anonymous):

if you have 4 sweets, and take away 3 sweets..how many sweets do you have left? here 'u' are the sweets

4 years ago
OpenStudy (dobby1):

u

4 years ago
OpenStudy (goformit100):

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4 years ago
OpenStudy (anonymous):

U

4 years ago
OpenStudy (anonymous):

yes, that is correct.

4 years ago
OpenStudy (anonymous):

What is f + 2e - (-3f)

4 years ago
OpenStudy (anonymous):

well two negatives make a positive so in essence you have f+2e+3f so group the f's together so f+3f+2e=(1+3)f+2e = ?f+2e ? how many f's do you have?

4 years ago
OpenStudy (anonymous):

4 ?

4 years ago
OpenStudy (anonymous):

Is 4e + 2e the answer ?

4 years ago
OpenStudy (anonymous):

4 is correct but it would be 4f+2e

4 years ago
OpenStudy (anonymous):

What is ; (a) × (-2a)

4 years ago
OpenStudy (anonymous):

what is a * a?

4 years ago
OpenStudy (anonymous):

A ?

4 years ago
OpenStudy (anonymous):

what is 2x2?

4 years ago
OpenStudy (anonymous):

4

4 years ago
OpenStudy (anonymous):

yes, so 2*2=2^2=4 ie it equals two squared so 3*3 is 3 squared 4*4 is four squared so a*a is .....?

4 years ago
OpenStudy (anonymous):

A squared

4 years ago
OpenStudy (anonymous):

yes, but note it is a little 'a' not a big 'A' - you can't change the notation so a*-2a = -2*a*a = ?

4 years ago
OpenStudy (anonymous):

I don't know that answer

4 years ago
OpenStudy (anonymous):

okay, so you just told me that a*a was 'a squared' right? so if you have -2 * 'a squared' the answer is just \[-2a ^{2}\]

4 years ago
OpenStudy (anonymous):

Ohh okay , so the answer for my question is -2a squared

4 years ago
OpenStudy (anonymous):

?

4 years ago
OpenStudy (anonymous):

yes that's correct

4 years ago
OpenStudy (anonymous):

Your really smart :)

4 years ago
OpenStudy (anonymous):

i'm not at all, but thankyou

4 years ago
OpenStudy (anonymous):

What is ; b(b + c) -2 (b - c)

4 years ago
OpenStudy (anonymous):

?

4 years ago
OpenStudy (anonymous):

so if you expand your brackets you will get (b*b)+(b*c)-(2*b)+(2*c) what does that give you?

4 years ago
OpenStudy (anonymous):

I don't know that one

4 years ago
OpenStudy (anonymous):

I think .. I don't know :(

4 years ago
OpenStudy (anonymous):

well at least try...come on. I can't give you the answers, but I can help you if you try.

4 years ago
OpenStudy (anonymous):

4b - 2c ?

4 years ago
OpenStudy (anonymous):

okay, you kind of have the right idea, when i said to you before, what is a*a, what did you say?

4 years ago
OpenStudy (anonymous):

a squared

4 years ago
OpenStudy (anonymous):

right, so what is b*b?

4 years ago
OpenStudy (anonymous):

b squared

4 years ago
OpenStudy (anonymous):

Yes! So that is the first bracket sorted! so we have (b*b)+(b*c)-(2*b)+(2*c) so this now equals \[b ^{2}+ (b \times c)-(2 \times b)+(2 \times c)\] so if you have 2 x c, that just equals 2c right?

4 years ago
OpenStudy (anonymous):

Correct

4 years ago
OpenStudy (anonymous):

okay so if you have 2 x c=2c 3 x c=3c then b x c = ??

4 years ago
OpenStudy (anonymous):

bc

4 years ago
OpenStudy (anonymous):

right! so look at this formula again: (b x b)+(b x c)-(2 x b)+(2 x c) what do you have?

4 years ago
OpenStudy (anonymous):

b squared + bc - 2b + 2c

4 years ago
OpenStudy (anonymous):

that's it! that's your answer

4 years ago
OpenStudy (anonymous):

2x + 5 = 10 , that one is easy

4 years ago
OpenStudy (anonymous):

so what do you get for x?

4 years ago
OpenStudy (anonymous):

I don't know, show me how to do the working

4 years ago
OpenStudy (anonymous):

okay so you need to rearrange: ax+b=c ax=c-b x=(c-b)/a

4 years ago
OpenStudy (anonymous):

i'm going now, as i have my own studying to do good luck

4 years ago
OpenStudy (anonymous):

Thank you

4 years ago
OpenStudy (anonymous):

So x = 5/2

4 years ago