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OpenStudy (anonymous):
if you have 4 sweets, and take away 3 sweets..how many sweets do you have left?
here 'u' are the sweets
OpenStudy (dobby1):
u
OpenStudy (goformit100):
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OpenStudy (anonymous):
U
OpenStudy (anonymous):
yes, that is correct.
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OpenStudy (anonymous):
What is f + 2e - (-3f)
OpenStudy (anonymous):
well two negatives make a positive so in essence you have
f+2e+3f
so group the f's together
so
f+3f+2e=(1+3)f+2e = ?f+2e ?
how many f's do you have?
OpenStudy (anonymous):
4 ?
OpenStudy (anonymous):
Is 4e + 2e the answer ?
OpenStudy (anonymous):
4 is correct but it would be 4f+2e
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OpenStudy (anonymous):
What is ; (a) × (-2a)
OpenStudy (anonymous):
what is a * a?
OpenStudy (anonymous):
A ?
OpenStudy (anonymous):
what is 2x2?
OpenStudy (anonymous):
4
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OpenStudy (anonymous):
yes, so 2*2=2^2=4
ie it equals two squared
so 3*3 is 3 squared
4*4 is four squared
so a*a is .....?
OpenStudy (anonymous):
A squared
OpenStudy (anonymous):
yes, but note it is a little 'a' not a big 'A' - you can't change the notation
so
a*-2a = -2*a*a = ?
OpenStudy (anonymous):
I don't know that answer
OpenStudy (anonymous):
okay, so you just told me that a*a was 'a squared' right?
so if you have -2 * 'a squared'
the answer is just \[-2a ^{2}\]
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OpenStudy (anonymous):
Ohh okay , so the answer for my question is -2a squared
OpenStudy (anonymous):
?
OpenStudy (anonymous):
yes that's correct
OpenStudy (anonymous):
Your really smart :)
OpenStudy (anonymous):
i'm not at all, but thankyou
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OpenStudy (anonymous):
What is ; b(b + c) -2 (b - c)
OpenStudy (anonymous):
?
OpenStudy (anonymous):
so if you expand your brackets you will get
(b*b)+(b*c)-(2*b)+(2*c)
what does that give you?
OpenStudy (anonymous):
I don't know that one
OpenStudy (anonymous):
I think .. I don't know :(
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OpenStudy (anonymous):
well at least try...come on. I can't give you the answers, but I can help you if you try.
OpenStudy (anonymous):
4b - 2c ?
OpenStudy (anonymous):
okay, you kind of have the right idea,
when i said to you before, what is a*a, what did you say?
OpenStudy (anonymous):
a squared
OpenStudy (anonymous):
right,
so what is b*b?
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OpenStudy (anonymous):
b squared
OpenStudy (anonymous):
Yes! So that is the first bracket sorted!
so we have (b*b)+(b*c)-(2*b)+(2*c)
so this now equals \[b ^{2}+ (b \times c)-(2 \times b)+(2 \times c)\]
so if you have 2 x c, that just equals 2c right?
OpenStudy (anonymous):
Correct
OpenStudy (anonymous):
okay so if you have
2 x c=2c
3 x c=3c
then b x c = ??
OpenStudy (anonymous):
bc
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OpenStudy (anonymous):
right!
so look at this formula again:
(b x b)+(b x c)-(2 x b)+(2 x c)
what do you have?
OpenStudy (anonymous):
b squared + bc - 2b + 2c
OpenStudy (anonymous):
that's it! that's your answer
OpenStudy (anonymous):
2x + 5 = 10 , that one is easy
OpenStudy (anonymous):
so what do you get for x?
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OpenStudy (anonymous):
I don't know, show me how to do the working
OpenStudy (anonymous):
okay so you need to rearrange:
ax+b=c
ax=c-b
x=(c-b)/a
OpenStudy (anonymous):
i'm going now, as i have my own studying to do
good luck