Mathematics
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OpenStudy (anonymous):
in triangle ABC, E is the midpoint of AC and D is the midpoint of CB. if DF is parallel to BE, find the length of side AB.
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OpenStudy (anonymous):
Is there an image?
jhonyy9 (jhonyy9):
us proportionalitie of sides
jhonyy9 (jhonyy9):
first try drawing it
OpenStudy (anonymous):
|dw:1382890008091:dw| here is the figure
jhonyy9 (jhonyy9):
so if D is the midpoint of CB what will be the lenght of CB ?
this is easy
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OpenStudy (anonymous):
10? i'm not sure
jhonyy9 (jhonyy9):
yes you are right
jhonyy9 (jhonyy9):
so then you know CB=10
OpenStudy (anonymous):
then?
jhonyy9 (jhonyy9):
now you can writing the proportionalitie of sides
CD CB
---- = ----
FD BF
and from this you can calculi easy the BF
ok?
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OpenStudy (anonymous):
BF= 6
jhonyy9 (jhonyy9):
5 10
--- = ---
3 BF
cross multiplie
5*BF = 3*10
yes you are right
OpenStudy (anonymous):
what's next after getting BF?
jhonyy9 (jhonyy9):
the same you can calculi CE
jhonyy9 (jhonyy9):
CF FD
--- = ----
CE EB
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OpenStudy (anonymous):
CE- 8 am i correct?
jhonyy9 (jhonyy9):
then CE= (EB*CF)/FD
jhonyy9 (jhonyy9):
sorry BE=6 not BF
BF not exist
jhonyy9 (jhonyy9):
yes CE=8
jhonyy9 (jhonyy9):
so E is the midpoint of AC what mean AC= ?
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jhonyy9 (jhonyy9):
then the lenght of AC = ?
OpenStudy (anonymous):
AC= 16
OpenStudy (anonymous):
then AB = 10
OpenStudy (anonymous):
is it correct?
jhonyy9 (jhonyy9):
how you have got AB=10 ?
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OpenStudy (anonymous):
\[\left(\begin{matrix}CE \\ AC\end{matrix}\right)= \left(\begin{matrix}FD \\ BE\end{matrix}\right)\]
OpenStudy (anonymous):
then by pythagorean theorem..
jhonyy9 (jhonyy9):
ok i understand it now
you are right
OpenStudy (anonymous):
Yaay.. thanks a lot :)
jhonyy9 (jhonyy9):
my pleasure
good luck