Mathematics
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OpenStudy (anonymous):
find the f-1 the inverse for f(x)= (x-1)^3
Help
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OpenStudy (lukecrayonz):
switch y and x around, solve.
OpenStudy (anonymous):
y=(x-1)^3
x=(y-1)^3 than what do i do after that
myininaya (myininaya):
Solve for y.
OpenStudy (anonymous):
details please
terenzreignz (terenzreignz):
Well, best get rid of that ^3.
How do you go about that?
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OpenStudy (anonymous):
square root???
terenzreignz (terenzreignz):
almost... but that's for getting rid of ^2 (squares)
How do you get rid of the ^3 (cube) ?
;)
OpenStudy (anonymous):
i thought thats where u come in place and tell me
terenzreignz (terenzreignz):
the cube root?
OpenStudy (anonymous):
i dont know
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terenzreignz (terenzreignz):
Get the cube root of both sides of
\[\Large x = (y-1)^3\]
terenzreignz (terenzreignz):
??
\[\Large \sqrt[3]x = \sqrt[3]{(y-1)^3 }\]
OpenStudy (anonymous):
than it x=\[\sqrt[3]{y-1?}\]
terenzreignz (terenzreignz):
Not exactly, no.
OpenStudy (anonymous):
im confused
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terenzreignz (terenzreignz):
\[\Large \sqrt[3]{p^3}=\color{red}?\]
OpenStudy (anonymous):
x
OpenStudy (anonymous):
lol i dont know
terenzreignz (terenzreignz):
pardon? lol
OpenStudy (anonymous):
its been almost 10yrs ago since i have takin algebra in high school so i need major help as u see
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terenzreignz (terenzreignz):
Shame, that.
Perhaps you should recall your laws of exponents?
OpenStudy (anonymous):
ayy ayy captain