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Pre-Algebra
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\[\frac{ q-3 }{ -5 } \times \frac{ 3q }{ q-4 }\]
do the top and bottom seperatly first so (q-3)3q= and -5(q-4)=
3q^2-6q and -5q+20
3q^2 - 9q for the numerator
\[\frac{ 3q^2-9q }{ -5+20 }\]
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-5q***
Duh. Lol. I'm just tired.
Now how do I find the restrictions?
Well the excluded values?
set then bottom = to 0 and any values you get are restricted bc you can not divide by 0
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I think it's \[q \neq5\]
4 bc 4*5=20 and 20-20=0
Yeah sorry. I forgot the +20 on the bottom.
glad to help
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