Question

Differentiate:
G(x)=sqrt(1-x^2) * arccos(x)

Answer 1

I got
\[G'(x)=-\frac{ \arccos(x) }{ \sqrt{1-x^2} }-1\]
but the book says there should be an extra x in the numerator

Answer 2

know about the chain rule ?

Answer 3

Yes, I'm guessing that's where I slipped

Answer 4

d/dx (sqrt(1-x^2)) = 1/2 sqrt (1-x^2) times d/dx (1-x^2)
and whats d/dx (1-x^2) = ...?

Answer 5

I thought d/dx(1-x^2) is just 2 no?

Answer 6

I mean -2

Answer 7

d/dx x^2 = ... ?

Answer 8

*facepalm* 2x

Answer 9

I was thinking the x turns into a 1 and leaves 2 alone, thanks

Answer 10

welcome ^_^