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Mathematics 14 Online
OpenStudy (anonymous):

Hi all! I'd like to double check. "differentiate (cosx)/(1-sinx)"

OpenStudy (anonymous):

So I used the quotient rule and got (-sinx+sin^2x+cos^2x)/(1-sinx)^2

hartnn (hartnn):

correct! and whats sin^2 x+cos^2x =... ?

OpenStudy (anonymous):

after simplifying a bit

OpenStudy (anonymous):

umm

OpenStudy (anonymous):

gah identities

OpenStudy (anonymous):

1? I cant remember

hartnn (hartnn):

you got to remember them

hartnn (hartnn):

yes, that = 1

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

so 1-sinx

OpenStudy (anonymous):

in the numerator

hartnn (hartnn):

something getting cancelled ?

OpenStudy (anonymous):

mhm so then its 1/(1-sinx)

hartnn (hartnn):

yup!

OpenStudy (anonymous):

:D

OpenStudy (anonymous):

Ok, I think I should look over those identities again :)

OpenStudy (anonymous):

thanks again as always ^_^

hartnn (hartnn):

use them as many times as you can, you will automatically remember it welcome ^_^

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