Question

Someone help! Ok, so I have this equation her that I solved. 2x+3y=1200
3y=-2x+1200
(3/3)y= (-2/3)x+(1200/3)
y=(-2/3)x+400
How would I graph this using the slope- intercept method?

Answer 1

well..the y intercept is 400.

The x intercept, you can find by subbing in 0 for y.
2x + 3(0) = 1200
2x = 1200
x = 600.

plot the points (0,400) and (600,0). Then connect the lines.
You can even go to the y intercept (0,400) and since the slope is -2/3, you come down 2 and go to the right 3 (thats a point on the line) then go down 2 again and to the right 3...all the way until you cross the x axis at 600.

Answer 2

Thank you so much!

Answer 3

anytime :)

Answer 4

@texaschic101 Do you know how I would write the equation in function notation?

Answer 5

y = -2/3x + 400
f(x) = -2/3x + 400 ==> function notation