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help... standard form. The line through (1, -4) and parallel to 2x +3y = 4.
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can you find slope of 2x+3y=4 ?
i don't know how, that is my problem....
can you isolate y from 2x+3y =4 ?
divide 3 on both sides?????
start by subtracting 2x from both sides then divide 3
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y=4-2x/3
compare that with y=mx+c where m= slope, so what u get 'm' as?
4????
basically the co-efficient of 'x' is slope here it is m = -2/3
so, now we have slope m=-2/3 , point x1=1, y1=-4
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just plug these in y-y1=m (x-x1)
y+4=-2/3(x-1)
yes! just simplify that start by multiplying 3 on both sides
3(y+4)=-2(x-1) 3y+12=-2x+2
add 2x on both sides...
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2x+3y+12=-2x+2 2x+3y+12=2 2x+3y=-10
correct! :)
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