Question

An object is thrown in the air from an initial height of 250 feet, with an initial upward velocity of 50 feet/second? • How long will the object be in the air?
•What will the velocity of the object be after 2 seconds?

Answer 1

Velocity final = velocity initial + acceleration (due to gravity) * time.

Velocity when the object gets to the highest point (and is about to start falling towards the ground due to velocity) is zero. Therefore, the equation is 0 = 50 * -32.17*t
So time is -50/-32.17, which is 50/32.17 seconds.

From this we can easily calculate the velocity of the object after 2 seconds.

Vf = 50 + -32.17*2 = -14.34 ft/s (so going towards the ground).

Now we need to account for the fact that the object is thrown from an initial height of 250 feet.