Derivative using quotient rule, just need to check if my work is correct.
x^2 + e^x / x^2 - e^x
f(x) = x^2 + e^x
f'(x) = 2x + e^x
g(x) = x^2 - e^x
g'(x) =2x - e^x
(2x + e^x)(x^2 - e^x) - (2x-e^x)(x^2+e^x)/(x^2-e^x)^2
?

Question

Derivative using quotient rule, just need to check if my work is correct.
x^2 + e^x  / x^2 - e^x
f(x) = x^2 + e^x
f'(x) = 2x + e^x
g(x) = x^2 - e^x
g'(x) =2x - e^x
(2x + e^x)(x^2 - e^x) - (2x-e^x)(x^2+e^x)/(x^2-e^x)^2 
?

anonymous · Answer

dang shamil @_@

anonymous · Answer

it equals peach, what else? ^_^

shamil98 · Answer

o.o

anonymous · Answer

@shamil98 I was never here...........┌(-_-) ┐└(-_-)┘┌(-_-) ┐└(-_-)┘
♪┏(・o･)┛♪┗ ( ･o･) ┓♪┏ ( ) ┛♪┗ (･o･ ) ┓♪┏(･o･)┛

shamil98 · Answer

@Luigi0210 yo is dis rite

luigi0210 · Answer

It should be:
$$\LARGE D(\frac{f(x)}{g(x)})=\frac{g(x)f'(x)-f(x)g'(x)}{(g(x))^2}$$
I don't think the order matters though, so yea it's correct

shamil98 · Answer

Oh, I was using the form from wikipedia lol, thanks