If parallelogram JKLM is rotated 270° clockwise around the origin, what are the coordinates of the endpoints of the side congruent to side KL in the image parallelogram? K'(-4, -6); L'(3, -3) K'(-6, -4); L'(-3, -3) K'(6, 4); L'(3, 3) K'(-4, 6); L'(-3, -3)
2.If pentagon ABCDE is rotated 180° around the origin to create pentagon A'B'C'D'E', what is the ordered pair of point A'? (2, -4) (-4, -2) (-2, -4) (4, 2)
For your pentagon.. 180 degrees rotation is (A,B) ==> (-A,-B) so (-2,4) -- > (2,-4)
Now, for your 270 degree rotation. (x,y) becomes (-y,x) K - (-5,6) becomes (-6,-5) L - (-3,3) becomes (-3,-3)
im really trying...i just dont understand this at all, thanks though ...
Yo jon why did you copy that from this ? http://openstudy.com/study#/updates/4fbebd98e4b0dd370c76bbf2
Don't plagiarize...
lololol
anyways bri, do you understand the rotation formulas? for 180 degrees rotation (x,y) becomes ( -x,-y) for 270 degrees rotation (x,y) becomes ( -y,x)
uhm...im still sooo confused, i appreciate the help... so for the first one i got...c And the second one i got b? is that right ?
OHH!! that makes more since, i didnt really understand the formula!
The first one is B. (-6,-4) , (-3,-3)
Sorry I thought the y original x coordinate was a 5.
K - (-4,6) becomes (-6,-4)* L - (-3,3) becomes (-3,-3)
There, since shamil is being a wingspan, let him hepl you!
thanks for your help jon!
Cuz you tried jon:P
wait are you sure that one is B?
Yes.
alright thanks ! and for the next one, i rotated it, i think right, i got c ? is that right
Point A is at (-2,4) what is (-x,-y) ?
lul
(2,-4) @brianna98bri is your answer..
thanks...im starting to get it, thanks for being patient !
Join our real-time social learning platform and learn together with your friends!