Ask your own question, for FREE!
Mathematics 11 Online
OpenStudy (anonymous):

What is the solution of the linear-quadratic system of equations?

OpenStudy (anonymous):

\[x^{2}+5x-3 \] y-x=2

OpenStudy (anonymous):

@agent0smith

OpenStudy (agent0smith):

I think the first one should be equal to something, is that all there is?

OpenStudy (anonymous):

my bad its supposed to be y=x^2+5x-3

OpenStudy (agent0smith):

K. Well we can probably solve it using substitution... since we have y-x = 2 add x to both sides to get y = 2+x got it so far?

OpenStudy (anonymous):

yes you are just putting it into standard form to make it easier to solve right?

OpenStudy (agent0smith):

well we're putting it that way because... y=x^2+5x-3 we know y = x+2 from above, so let's replace that y there with x+2... x+2=x^2+5x-3 now we can try finding x...

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!