Question

http://prntscr.com/20eujt

Answer 1

@mathkid1 u here? xD

Answer 2

yeah

Answer 3

\[
\sqrt[3]{2mn} \cdot \sqrt[3]{4m^2n^2} =
\bigg[ \sqrt[3]{2} \cdot \sqrt[3]{m} \cdot \sqrt[3]{n} \bigg] \cdot \bigg[ \sqrt[3]{4} \cdot\sqrt[3]{m^2} \cdot \sqrt[3]{n^2}\bigg] = \\
= \bigg[ \sqrt[3]{2} \cdot \sqrt[3]{2} \cdot \sqrt[3]{2} \bigg]
\cdot \bigg[ \sqrt[3]{m} \cdot\sqrt[3]{m} \cdot\sqrt[3]{m}\bigg]
\cdot \bigg[ \sqrt[3]{n} \cdot\sqrt[3]{n} \cdot\sqrt[3]{n}\bigg] = \\
= \bigg(\sqrt[3]{2} \bigg)^3 \cdot \bigg( \sqrt[3]{m} \bigg)^3 \cdot \bigg( \sqrt[3]{n} \bigg)^3 = 2mn
\]

Answer 4

@pitamar http://www.wolframalpha.com/input/?i=%5E3+sqrt+2mn+*+%5E3+sqrt+4m%5E2n%5E2 looks more like A no?

Answer 5

Perhaps I did a dumb mistake. lemme check

Answer 6

http://www.wolframalpha.com/input/?i=%5E3+sqrt+2mn+*+%5E3+sqrt+4m%5E2n%5E2 >.< my bad XD

Answer 7

okay :D

Answer 8

http://www.wolframalpha.com/input/?i=%5E3+sqrt+%282mn%29+*+%5E3+sqrt+4m%5E2n%5E2

Answer 9

so the answer's B ?

Answer 10

@pitamar so its A right? :)

Answer 11

you wrote a wrong equation, you did sqrt 2 instead of sqrt the whole thing. What I wrote says:
Alternate form assuming m and n are positive:
2mn
Which is closest to what I see there...

Answer 12

@pitamar oh :O my bad!

Answer 13

How the heck did you edit a message????

Answer 14

@pitamar who me? o-o I didnt do anything XD

Answer 15

I gave ya a medal though O-o

Answer 16

Oh sorry I've read the "My bad" at top post and thought it was your second >.< hehe
thanks

Answer 17

@pitamar oh goodness XD its okay XD I was like, what did I do? o-o looks like it was just a misunderstanding, just like how I misunderstood the question XD and np, u deserved it :D