Question

Write an equation in slope-intercept form for the line that passes through the given point and is perpendicular to the graph of the equation.

2.(4,-2) y=3x+5

Answer 1

Perpendicular is opposite reciprocal
so, your slope would be -1/3
then plug in what you know to figure out b
y=mx+b
-2=(-1/3)(4)+b
Solve for b.
Then your equation should look like
y=-1/3x+b
(I don't what's b)

Answer 2

so its perpendicular to 3x - 5 so the slope (m) would be \[-\frac{ 1 }{ 3 }\]
(negative reciprocal)

Plug in all the things you know you know. the x coordinate 4 and the y coordinate is -2 so plug those into y = mx+b
BTW you now know m = -1/3
y = -2
x = 4
since they gave you the x and y coordinates the line passes through \[y=-\frac{ 1 }{ 3 }x + b\]

so \[-2 = (-\frac{ 1 }{ 3 })(4) + b\](basically i plugged in all the info they gave me)

solve for b
You get b = -2/3

so if u plug it into the slope intercept form equation;\[y = mx+b\]
You get the equation of the line is \[y = -\frac{ 1 }{ 3 }x - \frac{ 2 }{ 3 }\]

I THINK THATS THE CORRECT ANSWER BUT I MAY NOT BE RIGHT

(btw i usually am) lol ;)

ok hoped this helped!!!!