If FE=x+4 and BC=3x+6 what is FE
Are points E and F midpoints on the sides on which they lie? If so, this theorem can be used? The segment joining the midpoints of two sides of a triangle has length half that of the third side of the triangle. That would give: FE = (1/2)*(BC) x + 4 = (1/2)* (3x + 6) Solve for x. ----> This equation is true only if E and F are midpoints of the sides on which they lie on the triangle, @DeeBush96
On this thread, I found that E and F are midpoints. http://openstudy.com/users/deebush96#/updates/526f4d6de4b0e209601e5ccd
So, solve this for x: x + 4 = (1/2)* (3x + 6) Double both sides 2(x + 4) = 2*(1/2)* (3x + 6) 2x + 8 = 3x + 6 3x + 6 = 2x + 8 x = 8 - 6 x = ? @DeeBush96
2
After you get x, substitute it into the formula for FE. FE=x+4 FE = (?) + 4 = ?
So, FE = ?
is it 2
6
Correct. FE = 6.
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