How can you find t from this equation? :
\[(2)^{t/3} = (3)^{t/2} + 10,000\]
graph it maybe ?
can't we use any of the logs or something? :)
logs are of no use here, you mean below right ? \(\large (2)^{t/3} = (3)^{t/\color{red}{5}} + 10,000 \)
wait, haha, my brain is loading.. why's it 5? :) red
population A doubles in 3 hours population B triples in 5 hours you're stuck wid that problem eh ?
no, in 2 hours
no, i already got the answer for that problem. it's not 10,000 more. it's 10,000 times more.
oh ! then its real easy
\(\large (2)^{t/3} = (3)^{t/2} + 10,000 \)
typographical error at first. so the equation for my first problem was this: \[(2)^{t/3} = (3)^{t/2} * 10,000\] and i got the answer from using natural log according to one person who replied
but im just curious if the problems says, 10,000 more and not 10,000 times more.
yeah u can log and work it if its 10000 times
good, think about it :) let me knw if u find something interesting =))
hey wait a sec, \(\large (2)^{t/3} = (3)^{t/2} * 10,000\)
ahmmm, *brainstorming* haha. brainstorming with an empty brain. my brain is loading right now lol okay i'll tryyy
this is impossible right ? left side is growing very slow. so it can never reach right side
empty brain is always good, cuz u can fill it wid nice stuff... :)
really? it's impossible? so it's my teacher's fault why students can't get it. waoh
population A doubles in 3 hours population B triples in 2 hours B is way faster than A. so A cannot catchup B
maybe someday it will LOL
i remember, in ur other question, you have different numbers :- population A doubles in 3 hours population B triples in \(\color{red}{5}\) hours this is possible however.
wait, goin' to check that
okie :o
@ganeshie8 typographical error again! hahahaha im so sorry, it's 5 =)
so sorry so sorry so sorry hahaha
np :) just making sure.... you dont cuss ur teacher when there is no fault from her lol
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so it's \[(2)^{t/3} = (3)^{t/5} +10,000\]
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