Question

Given the functions...

Answer 1

f(n)=11 and \[g(n)=(\frac{ 3 }{ 4 })^{n-1}\]
combine them to create a geometric sequence and solve for the 9th term.

Answer 2

\[a_n=(11\times \frac{ 3 }{ 4 })^{n-1};a_9\approx24.301\]
\[a_n=11(\frac{ 3 }{ 4 })^{n-1}; a_9\approx1.101\]
\[a_n=11+(\frac{ 3 }{ 4 })^{n-1}; a_9\approx11.100\]
\[a_n=11-(\frac{ 3 }{ 4 })^{n-1};a_9\approx9.900\]