Question

A force of 200N, directed at 20 degree above the horizontal, is applied to move a 50kg cart (initially at rest) across a 10m level surface. What is the speeed of the cart at the end of the 10m distance?
Please

Answer 1

something wrong with my net. I didn't close the post

Answer 2

oh, ok, i was just going to ask you that

Answer 3

are you getting a wrong answer or no answer? or... where are you getting hung up at?

Answer 4

i don't know how to start

Answer 5

k
and is there any friction force?

Answer 6

no information about it. They give me multiple choices but I want to know how to solve it.

Answer 7

do I have to break the force to horizontal one? it is F cos 20?

Answer 8

do you wanna post up the multiple choices, and i'll work it out before I start teaching ^_^

Answer 9

ya, the force needs to be broken up into x and y components

Answer 10

ok
a)5.2m/s
b) 8.6 m/s
c) 8.9 m/s
d) 6.8 x10^2 m/s
e) 2.0 x 10^3 m/s

Answer 11

do you want the answer, too?

Answer 12

k,
nearly done...

Answer 13

k, i got it ^_^

Answer 14

so after you have the force in the x-direction:
200n * cos(20) = 187.9n

there are two equations to solve this:
F=ma
and
V^2 = V^2 + 2as

can you see which way to go now? ... ^_^

Answer 15

got you. I can do the rest. Thanks a lot. I need practice for my test next week.

Answer 16

great ^_^

Answer 17

I got the right answer lalalala.... thank you.

Answer 18

your welcome!
i'm on for 40 more min if you have any other physics questions

Answer 19

thank you, I will work on it , if I have problem I will not let you free. hehehe....

Answer 20

haha ^_^