Question

i need help with an implicit differentiation problem... y+yx= (x+y)/(2x-y)

Answer 1

i have y' + 4 = (2x-4)(1+') - (x+y)(2-y') / (2x -y)^2 and that is it :/

Answer 2

i'm not sure.. haha i am very bad at this..

Answer 3

my final answer was y'= (-16x^2+(16x-3)y-4y^2)/ (-4xy+x(4x-3) + y^2) is that right?

Answer 4

treat y as function of x, y(x). So it will have derivative, y'(x). The rest just use normal differentiation rules.
\(y'+y+xy'=\large\frac{(1+y')(2x-y)-(x+y)(2-y')}{x-y)^2}\)

Answer 5

the denominator hould be (2x-y)^2

Answer 6

so my numerator is correct?

Answer 7

yes