Question

Solve the equation of 2log (2y + 4) = log 9 + 2log (y -1).

Answer 1

A.
3
B.
5
C.
7
D.
21

Answer 2

How would i solve this ?

Answer 3

Condense the logs on the right side first.

Answer 4

log9+log2 first or log2(x-1)?

Answer 5

first bring the exponents up like this \[\Large \log (2y + 4)^2 = \log 9 + \log (y -1)^2\] then condense logs on the right

Answer 6

Sorry not sure how to do this could you walk me throught it?

Answer 7

Use the log rule log(a) + log(b) = log(a)(b)

Answer 8

eg log(x+3) + log(x-2) = log(x+3)(x-2)

Answer 9

log(9)(2y-1)^2

Answer 10

\[\Large \log (2y + 4)^2 = \log 9(y -1)^2 \]now you can just drop the logs on both sides, and solve for y. Logs are one-to-one functions so you can do that here.

eg if logx = logy then x = y

Answer 11

(2y+4)^2=9(2y-1)^2 would be the qeuation to solve

Answer 12

Yep