Express in simplest form 10 square root of 24 divide 2 square root of 2?
\[\frac{ 10\sqrt{24} }{ 2\sqrt{2} }\]
yeah
So what two numbers can you multiply together, one being a perfect square that goes into 24? a x b = 24 a or b should be a perfect square
4 and 6
Good
So, now what is the square root of 4?
2
So that comes to the outside... 10(2)\[10(2)\sqrt{6}\]
so that would be the answer
\[20\sqrt{6}\]
\[\frac{ 20\sqrt{6} }{ 2\sqrt{2} }\]
Okay thanks now I get it
So what is your final answer @farmergirl411
10 square root of 3
\[\frac{ 10\sqrt{6} }{ \sqrt{2}}\]
I forget if we can actually simplify those two radicals like that... let me double check
ok
Oh okay I just checked and it is \[10\sqrt{3}\]
ok thanks
\[\frac{ 10\sqrt{24} }{ 2\sqrt{2}} \\=\frac{ 10\sqrt{4 \times 6} }{ 2\sqrt{2}} \\=\frac{ 10\sqrt{4} \times \sqrt{6}}{ 2\sqrt{2}} \\= \frac{ 10(2)\sqrt{6}}{ 2\sqrt{2}} \\= 10\frac{\sqrt{6}}{\sqrt{2}} \\= 10\sqrt{\frac{6}{2}} \\= 10\sqrt{3}\]
Yeah, see that looks better... it was confusing me because I had the 6 and 2 under separate radicals...
I think I was thinking of addition...
or subtraction... you know?
Remember this rule \[\frac{\sqrt{a}}{\sqrt{b}} = \sqrt{\frac{a}{b}}\]
Will do! :D Thanks again @Hero
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