The probability that a train leaves on time is 0.8. The probability that the train arrives on time and leaves on time is 0.24. What is the probability that the train arrives on time given that it leaves on time?

Question

anonymous · Answer

$$P(A|B)=\frac{P(A\cap B)}{P(B)}$$\

anonymous · Answer

you got this?

anonymous · Answer

sooo .24/.8? because a&B would be B right?

anonymous · Answer

$$A\cap B$$ is A and B, i.e arrive on time and leave on time, so $P(A\cap B)=.24$ yes

anonymous · Answer

wait so it would be .24/.24? o.o;

anonymous · Answer

and $P(B)=.8$ because you are told it is
so yes, 
$$\frac{.24}{.8}=\frac{24}{80}=\frac{3}{10}$$

anonymous · Answer

oh no you were right the first time

anonymous · Answer

ohhh okay! Thank you!

anonymous · Answer

yw

anonymous · Answer

quite a mixture of problems
must be an on line class
little of this
little of that

anonymous · Answer

Yeah it's a review for Algebra 2 online, It's horrible. I only understood one unit of it. So trying to get the best grade before the final that i will probably fail xD

anonymous · Answer

how the hell is probability "algebra"

forget i asked

anonymous · Answer

haha there is a lot of things that i don't think should be in an algebra course that were in it

anonymous · Answer

I totally agree -.-