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\[12+3^{3}\sqrt{2n}=0\]
for n
((12/9)^2)/2=n
sorry 12/27 not 12/9
my choices are 64 32 -64 -32
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common meg get it together. grab a calculator
no, none of those answers are right
are you sure signs are correct? you have the sum of two positive number, it can never be zero
yes thats how it is written
There are two values out of the square root when you plug it back in. One negative, one positive. The negative one is the one that's true
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