Question

how to Input the equation of the given line in slope-intercept form.
https://media.glynlyon.com/g_alg02_2013/3/ui1.gif

Answer 1

can you get 2 points with coordinates from that picture?

Answer 2

i'm not sure how

Answer 3

what do you think is the coordinate where the line is touching the x-axis?

Answer 4

1?

Answer 5

( 0, 1) or (1, 0) ? or just (1, 1) ?

Answer 6

(0,1)?

Answer 7

x y
( 0, 1 ) ?

Answer 8

yes?

Answer 9

that means x = 0 and y = 1.....

Answer 10

so i just need to put those coordinates in slope intercept form?

Answer 11

well... sorta... you just need 2 points... anyhow lemme get a couple, let's say (2, 1) and (-1, -2)

so using those 2 points, you'd first find the slope
so \( \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&(a\quad ,&b)\quad &(c\quad ,&d)
\end{array}\\ \quad \\slope = m= \cfrac{rise}{run} \implies \cfrac{y_2-y_1}{x_2-x_1}\\ \quad \\
\textit{once you get the slope, you plug those values in the point-slope form}\\
y-y_1=m(x-x_1)\)

Answer 12

ohh.. shoot... aemm... one well... one sec

Answer 13

\(\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&(2\quad ,&1)\quad &(-1\quad ,&-2)
\end{array}\\ \quad \\slope = m= \cfrac{rise}{run} \implies \cfrac{y_2-y_1}{x_2-x_1}\\ \quad \\
\textit{once you get the slope, you plug those values in the point-slope form}\\
\color{red}{y-y_1=m(x-x_1)}
\)