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OpenStudy (samigupta8):
the real value of a for which x^2+i(a-1)x+5=0 will have a pair of conjugate complex roots is
a.1
b.all values
c.no values exist
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OpenStudy (anonymous):
put D<0
OpenStudy (samigupta8):
wait u r considering it wrong
question says pair of conjugate complex roots don't consider it to be irrational
OpenStudy (samigupta8):
@AllTehMaffs pls..hlp
OpenStudy (anonymous):
complex roots are always conjugate.........so dont bother bout it
id D>0 distinct real roots
D=0 only one real root
D<0 imaginary roots
OpenStudy (samigupta8):
then i m getting sumthing like dis values staisfying a^2-2a+21>0
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OpenStudy (samigupta8):
alltehmaffs do u also consider dat i should take d<0
OpenStudy (anonymous):
Yeah, because b^2 will always be negative
\[(i(a+1))^2 = -(a+1)^2
OpenStudy (anonymous):
\[(i(a+1))^2 = -(a+1)^2
\]
OpenStudy (anonymous):
bah, a-1. Sorry
OpenStudy (anonymous):
@AllTehMaffs she got her answer...
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OpenStudy (samigupta8):
yaa
OpenStudy (anonymous):
I'm a bit slow I think :P
OpenStudy (samigupta8):
i got 1 as my answer
OpenStudy (samigupta8):
no no don't think lyk dat
OpenStudy (anonymous):
^_^ thanks
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