Ask your own question, for FREE!
Mathematics 17 Online
OpenStudy (samigupta8):

the real value of a for which x^2+i(a-1)x+5=0 will have a pair of conjugate complex roots is a.1 b.all values c.no values exist

OpenStudy (anonymous):

put D<0

OpenStudy (samigupta8):

wait u r considering it wrong question says pair of conjugate complex roots don't consider it to be irrational

OpenStudy (samigupta8):

@AllTehMaffs pls..hlp

OpenStudy (anonymous):

complex roots are always conjugate.........so dont bother bout it id D>0 distinct real roots D=0 only one real root D<0 imaginary roots

OpenStudy (samigupta8):

then i m getting sumthing like dis values staisfying a^2-2a+21>0

OpenStudy (samigupta8):

alltehmaffs do u also consider dat i should take d<0

OpenStudy (anonymous):

Yeah, because b^2 will always be negative \[(i(a+1))^2 = -(a+1)^2

OpenStudy (anonymous):

\[(i(a+1))^2 = -(a+1)^2 \]

OpenStudy (anonymous):

bah, a-1. Sorry

OpenStudy (anonymous):

@AllTehMaffs she got her answer...

OpenStudy (samigupta8):

yaa

OpenStudy (anonymous):

I'm a bit slow I think :P

OpenStudy (samigupta8):

i got 1 as my answer

OpenStudy (samigupta8):

no no don't think lyk dat

OpenStudy (anonymous):

^_^ thanks

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!