Question

what should i do in this ...
2^8 × 8^2 × 4^-2 in the form 2n. ???

Answer 1

try to get the bases of them be same.
hint :
8 = 2^3
4 = 2^2

Answer 2

Put it in the form 2n or 2^n ?

Answer 3

2^n

Answer 4

Bigger hint: $$2^8 × 8^2 × 4^{-2} $$ $$=2^8 × (2^3)^2 × (2^2)^{-2} $$

Answer 5

there's another question....!! what is the formula of compund interest ? ;p

Answer 6

super hint :P
use these properties of exponents :
(a^m)^n = a^(m * n)
a^m * a^n = a^(m+n)

Answer 7

formatted super hint: $$(a^m)^n = a^{m * n}$$and
$$a^m * a^n = a^{m+n}$$

Answer 8

2^8 × 8^2 × 4^-2
2^8*(2^3)^2*(2^2)^-2
2^8*2^6*2^-4
as base of all the power is same that is 2
so the power will add up
2^(8+6-4)
2^10