Question

What is the relative extrema of h(x)=2x^3+5x^2-25x?

Answer 1

Find the derivative h'(x). Equate it to zero and solve for x. Those are the critical points. You can do the second derivative test to see if it is a maxima or a minima.

Answer 2

I equated the function to 0 and got 0, is that correct?

Answer 3

@ali1029 You need to find h' first.

Answer 4

How do I find h?

Answer 5

You mean h'?

Answer 6

h' means derivative of h.
You need to differentiate each term of 2x^3+5x^2-25x and equate it to 0.

Answer 7

oh okay, I didn't know it was h'. What do I need to do to differentiate each term and equate it to 0?