Question

Which is equal to (3 x^2 yz)(5x y^3 z^2)?
(Points : 1)
8x3y4z3

15x2y3z2

15x3y4z3

45x3y4z3

Answer 1

Which is equal to (3x2yz)(5xy3z2)?

8x^3 y^4 z^3

15x^2 y^3 z^2

15 x^3 y^4 z^3

45 x^3 y^4 z^3


I GOT C

Answer 2

\[(3x^{2}yz)(5xy^{3}z^{2}) = 15x^{3}y^{4}z^{3}\]

Answer 3

thank you :)

Answer 4

"c" because when multiplying variables you add the exponents

Answer 5

Bananas multiply bananas, apples multiply apples and pears multiply pears.
\[3*5 = 15\]
\[x^{2}*x = x^{3}\]
\[y*y^{3} = y^{4}\]
\[z*z^{2} = z^{3}\]
Combining everything from the right, you get the answer.
\[15x^{3}y^{4}z^{3}\]

Answer 6

yes what about 5x^2 / 5 x ^3 would the answer be 1x^-1?

Answer 7

or just x^-1?

Answer 8

\[\frac{ 5x^{2} }{ 5x^{3} } = \frac{ 1 }{ x }\]
Again, apples divide apples and pears divide pears.
\[\frac{ 5 }{ 5 }=1\]
\[\frac{ x^{2} }{ x^{3} }=\frac{ x*x }{ x*x*x }=\frac{ 1 }{ x }\]

Multiplying the apples times the pears, you get the answer, 1/x.

Answer 9

1x^-1 is the same as x^-1, as multiplying anything by one does absolutely nothing. (6 times 1 is 6, 8 times 1 is 8, etc.)

Answer 10

divide

Answer 11

so 6^-1 would be -6?

Answer 12

No, for any number you use, elevating it to a negative number, makes it go from the numerator to the denominator, or backwards if it's already in the denominator.
\[x^{-1} = \frac{ 1 }{ x }\]
So 6^-1 would be 1/6.

Answer 13

oh ok :)